Rightmost Digit
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 39389 Accepted Submission(s): 14863 Problem Description
Given a positive integer N, you should output the most right digit of N^N.
Input
The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow. Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Output
For each test case, you should output the rightmost digit of N^N.
Sample Input
2 3 4
Sample Output
7 6
Hint
In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7. In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6. Author
Ignatius.L
#include快速幂求余!#include #include using namespace std;long long int powermod(long long int a,long long int b,long long int c){ long long int ans = 1; a = a%c; while (b > 0) { if (b% 2 ==1) ans = ans * a %c; b = b/2; a = a* a %c; } return ans;}int main(){ int t; long long int n; cin >> t; while (t--) { cin >> n; cout < << endl; } return 0;}